std::ranges::equal

Two ranges are considered equal if they have the same number of elements and every pair of corresponding projected elements satisfies pred. That is, std::invoke (pred, std::invoke (proj1, *first1), std::invoke (proj2, *first2) ) returns true

The function-like entities described on this page are algorithm function objects (informally known as niebloids), that is:

• Explicit template argument lists cannot be specified when calling any of them.
• None of them are visible to argument-dependent lookup.
• When any of them are found by normal unqualified lookup as the name to the left of the function-call operator, argument-dependent lookup

Parameters

Return value

If the length of the range [ first1 ,  last1 ) does not equal the length of the range [first2, last2), returns false

If the elements in the two ranges are equal after projection, returns true.

Otherwise returns false.

Notes

ranges::equal should not be used to compare the ranges formed by the iterators from std::unordered_set, std::unordered_multiset, std::unordered_map, or std::unordered_multimap

When comparing entire containers or string views for equality, operator== for the corresponding type are usually preferred.

ranges::equal std::memcmp

Complexity

At most min(last1 - first1, last2 - first2)

However, if S1 and S2 both model std::sized_sentinel_for their respective iterators, and last1 - first1 != last2 - first2

Possible implementation

struct equal_fn
{
  template<std::input_iterator I1, std::sentinel_for<I1> S1,
           std::input_iterator I2, std::sentinel_for<I2> S2,
           class Pred = ranges::equal_to,
           class Proj1 = std::identity, class Proj2 = std::identity>
  requires std::indirectly_comparable<I1, I2, Pred, Proj1, Proj2>
  constexpr bool
      operator()(I1 first1, S1 last1, I2 first2, S2 last2,
                 Pred pred = {}, Proj1 proj1 = {}, Proj2 proj2 = {}) const
  {
      if constexpr (std::sized_sentinel_for<S1, I1> and std::sized_sentinel_for<S2, I2>)
          if (std::ranges::distance(first1, last1) != std::ranges::distance(first2, last2))
              return false;
 
      for (; first1 != last1; ++first1, (void)++first2)
          if (!std::invoke(pred, std::invoke(proj1, *first1), std::invoke(proj2, *first2)))
              return false;
      return true;
  }
 
  template<ranges::input_range R1, ranges::input_range R2,
           class Pred = ranges::equal_to,
           class Proj1 = std::identity, class Proj2 = std::identity>
  requires std::indirectly_comparable<ranges::iterator_t<R1>, ranges::iterator_t<R2>,
                                      Pred, Proj1, Proj2>
  constexpr bool
      operator()(R1&& r1, R2&& r2, Pred pred = {}, Proj1 proj1 = {}, Proj2 proj2 = {}) const
  {
      return (*this)(ranges::begin(r1), ranges::end(r1),
                     ranges::begin(r2), ranges::end(r2),
                     std::ref(pred), std::ref(proj1), std::ref(proj2));
  }
};
 
inline constexpr equal_fn equal;

Example

#include <algorithm>
#include <iomanip>
#include <iostream>
#include <ranges>
#include <string_view>
 
constexpr bool is_palindrome(const std::string_view s)
{
    namespace views = std::views;
    auto forward = s | views::take(s.size() / 2);
    auto backward = s | views::reverse | views::take(s.size() / 2);
    return std::ranges::equal(forward, backward);
}
 
void test(const std::string_view s)
{
    std::cout << std::quoted(s) << " is "
              << (is_palindrome(s) ? "" : "not ")
              << "a palindrome\n";
}
 
int main()
{
    test("radar");
    test("hello");
    static_assert(is_palindrome("ABBA") and not is_palindrome("AC/DC"));
}

"radar" is a palindrome
"hello" is not a palindrome

See also