std::ratio_add

The alias template std::ratio_add denotes the result of adding two exact rational fractions represented by the std::ratio specializations R1 and R2

The result is a std::ratio specialization std::ratio<U, V>, such that given Num == R1:: num * R2:: den + R2:: num * R1:: den and Denom == R1::den * R2::den (computed without arithmetic overflow), U is std::ratio <Num, Denom> :: num and V is std::ratio <Num, Denom> :: den

Notes

If U or V is not representable in std::intmax_t, the program is ill-formed. If Num or Denom is not representable in std::intmax_t, the program is ill-formed unless the implementation yields correct values for U and V

The above definition requires that the result of std::ratio_add<R1, R2> be already reduced to lowest terms; for example, std:: ratio_add < std::ratio < 1, 3 >, std::ratio < 1, 6 >> is the same type as std::ratio<1, 2>

Example

#include <iostream>
#include <ratio>
 
int main()
{
    using two_third = std::ratio<2, 3>;
    using one_sixth = std::ratio<1, 6>;
    using sum = std::ratio_add<two_third, one_sixth>;
 
    std::cout << "2/3 + 1/6 = " << sum::num << '/' << sum::den << '\n';
}

2/3 + 1/6 = 5/6

See also