std::is_constructible, std::is_trivially_constructible, std::
Defined in header <type_traits>
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||
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template
<
class T, class... Args
>
struct is_constructible; |
(1) | (since C++11) |
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template
<
class T, class... Args
>
struct is_trivially_constructible; |
(2) | (since C++11) |
|
template
<
class T, class... Args
>
struct is_nothrow_constructible; |
(3) | (since C++11) |
T is an object or reference type and the variable definition
T obj(
std::declval
<Args>
(
)...)
;
is well-formed, provides the member constant value equal to true. In all other cases, value is false.For the purposes of this check, the variable definition is never interpreted as a function declaration, and the use of std::declval is not considered an odr-use. Access checks are performed as if from a context unrelated to
T and any of the types in Args
noexcept.If T or any type in the parameter pack Args is not a complete type, (possibly cv-qualified) void
If an instantiation of a template above depends, directly or indirectly, on an incomplete type, and that instantiation could yield a different result if that type were hypothetically completed, the behavior is undefined.
If the program adds specializations for any of the templates described on this page, the behavior is undefined.
Helper variable templates
|
template
<
class T, class... Args
>
inline constexpr bool is_constructible_v = |
(since C++17) | |
|
template
<
class T, class... Args
>
inline constexpr bool is_trivially_constructible_v = |
(since C++17) | |
|
template
<
class T, class... Args
>
inline constexpr bool is_nothrow_constructible_v = |
(since C++17) | |
Inherited from std::integral_constant
Member constants
value [static] |
true if T is constructible from Args..., false otherwise (public static member constant) |
Member functions
operator bool |
converts the object to bool, returns value
(public member function) |
operator() (C++14) |
returns value (public member function) |
Member types
| Type | Definition |
value_type
|
bool |
type
|
std::integral_constant < bool, value> |
Notes
In many implementations, is_nothrow_constructible also checks if the destructor throws because it is effectively noexcept(T(arg)). Same applies to is_trivially_constructible, which, in these implementations, also requires that the destructor is trivial: GCC bug 51452
LWG issue 2116
Example
#include <iostream> #include <type_traits> class Foo { int v1; double v2; public: Foo(int n) : v1(n), v2() {} Foo(int n, double f) noexcept : v1(n), v2(f) {} }; int main() { auto is = [](bool o) { return (o ? "\t" "is " : "\t" "isn't "); }; std::cout << "Foo ...\n" << is(std::is_trivially_constructible_v<Foo, const Foo&>) << "Trivially-constructible from const Foo&\n" << is(std::is_trivially_constructible_v<Foo, int>) << "Trivially-constructible from int\n" << is(std::is_constructible_v<Foo, int>) << "Constructible from int\n" << is(std::is_nothrow_constructible_v<Foo, int>) << "Nothrow-constructible from int\n" << is(std::is_nothrow_constructible_v<Foo, int, double>) << "Nothrow-constructible from int and double\n"; }
Output:
Foo ...
is Trivially-constructible from const Foo&
isn't Trivially-constructible from int
is Constructible from int
isn't Nothrow-constructible from int
is Nothrow-constructible from int and double
See also
| checks if a type has a default constructor (class template) |
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(C++11)(C++11)(C++11)
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checks if a type has a copy constructor (class template) |
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(C++11)(C++11)(C++11)
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checks if a type can be constructed from an rvalue reference (class template) |
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(C++20)
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specifies that a variable of the type can be constructed from or bound to a set of argument types (concept) |