Copy assignment operator
A copy assignment operator is a non-template non-static member function with the name operator=
Syntax
For the formal copy assignment operator syntax, see function declaration. The syntax list below only demonstrates a subset of all valid copy assignment operator syntaxes.
return-type operator=( parameter-list );
|
(1) | ||||||||
return-type operator=( parameter-list ) function-body
|
(2) | ||||||||
return-type operator=( parameter-list-no-default ) = default;
|
(3) | (since C++11) | |||||||
return-type operator=( parameter-list ) = delete;
|
(4) | (since C++11) | |||||||
return-type
class-name ::
operator=(
parameter-list )
function-body
|
(5) | ||||||||
return-type class-name :: operator=( parameter-list-no-default ) = default;
|
(6) | (since C++11) | |||||||
class-name | - | the class whose copy assignment operator is being declared, the class type is given as T in the descriptions below
|
parameter-list | - | a parameter list of only one parameter, which is of type T , T& , const T&, volatile T& or const volatile T&
|
parameter-list-no-default | - | a parameter list of only one parameter, which is of type T , T& , const T&, volatile T& or const volatile T&
|
function-body | - | the function body of the copy assignment operator |
return-type | - | any type, but T& is favored in order to allow chaining asssignments
|
Explanation
struct X { X& operator=(X& other); // copy assignment operator X operator=(X other); // pass-by-value is allowed // X operator=(const X other); // Error: incorrect parameter type }; union Y { // copy assignment operators can have syntaxes not listed above, // as long as they follow the general function declaration syntax // and do not viloate the restrictions listed above auto operator=(Y& other) -> Y&; // OK: trailing return type Y& operator=(this Y& self, Y& other); // OK: explicit object parameter // Y& operator=(Y&, int num = 1); // Error: has other non-object parameters };
The copy assignment operator is called whenever selected by overload resolution, e.g. when an object appears on the left side of an assignment expression.
Implicitly-declared copy assignment operator
If no user-defined copy assignment operators are provided for a class type, the compiler will always declare one as an inline public member of the class. This implicitly-declared copy assignment operator has the form T& T:: operator = ( const T& )
- each direct base
B
ofT
has a copy assignment operator whose parameters areB
or const B& or const volatile B& - each non-static data member
M
ofT
of class type or array of class type has a copy assignment operator whose parameters areM
or const M& or const volatile M&
Otherwise the implicitly-declared copy assignment operator is declared as T& T::operator=(T&)
Due to these rules, the implicitly-declared copy assignment operator cannot bind to a volatile lvalue argument.
A class can have multiple copy assignment operators, e.g. both T& T::operator=(T&) and T& T::operator=(T). If some user-defined copy assignment operators are present, the user may still force the generation of the implicitly declared copy assignment operator with the keyword default (since C++11)
The implicitly-declared (or defaulted on its first declaration) copy assignment operator has an exception specification as described in dynamic exception specification(until C++17) noexcept specification(since C++17)
Because the copy assignment operator is always declared for any class, the base class assignment operator is always hidden. If a using-declaration
Implicitly-defined copy assignment operator
If the implicitly-declared copy assignment operator is neither deleted nor trivial, it is defined (that is, a function body is generated and compiled) by the compiler if odr-used or needed for constant evaluation (since C++14) . For union types, the implicitly-defined copy assignment copies the object representation (as by std::memmove
The implicitly-defined copy assignment operator for a class
|
(since C++14) (until C++23) |
The implicitly-defined copy assignment operator for a class |
(since C++23) |
The generation of the implicitly-defined copy assignment operator is deprecated if |
(since C++11) |
Deleted copy assignment operator
An implicitly-declaredor explicitly-defaulted(since C++11) copy assignment operator for class T
is undefined(until C++11)
defined as deleted(since C++11)
T
has a non-static data member of a const-qualified non-class type (or possibly multi-dimensional array thereof).T
has a non-static data member of a reference type.-
T
has a potentially constructed subobject of class typeM
(or possibly multi-dimensional array thereof) such that the overload resolution as applied to findM
- does not result in a usable candidate, or
- in the case of the subobject being a variant member, selects a non-trivial function.
The implicitly-declared copy assignment operator for class |
(since C++11) |
Trivial copy assignment operator
The copy assignment operator for class T
is trivial if all of the following is true:
- it is not user-provided (meaning, it is implicitly-defined or defaulted);
T
has no virtual member functions;T
has no virtual base classes;- the copy assignment operator selected for every direct base of
T
is trivial; - the copy assignment operator selected for every non-static class type (or array of class type) member of
T
is trivial.
A trivial copy assignment operator makes a copy of the object representation as if by std::memmove
Eligible copy assignment operator
A copy assignment operator is eligible if it is either user-declared or both implicitly-declared and definable. |
(until C++11) |
A copy assignment operator is eligible if it is not deleted. |
(since C++11) (until C++20) |
A copy assignment operator is eligible if all following conditions are satisfied:
|
(since C++20) |
Triviality of eligible copy assignment operators determines whether the class is a trivially copyable type.
Notes
If both copy and move assignment operators are provided, overload resolution selects the move assignment if the argument is an rvalue (either a prvalue such as a nameless temporary or an xvalue such as the result of std::move), and selects the copy assignment if the argument is an lvalue
It is unspecified whether virtual base class subobjects that are accessible through more than one path in the inheritance lattice, are assigned more than once by the implicitly-defined copy assignment operator (same applies to move assignment
See assignment operator overloading for additional detail on the expected behavior of a user-defined copy-assignment operator.
Example
#include <algorithm> #include <iostream> #include <memory> #include <string> struct A { int n; std::string s1; A() = default; A(A const&) = default; // user-defined copy assignment (copy-and-swap idiom) A& operator=(A other) { std::cout << "copy assignment of A\n"; std::swap(n, other.n); std::swap(s1, other.s1); return *this; } }; struct B : A { std::string s2; // implicitly-defined copy assignment }; struct C { std::unique_ptr<int[]> data; std::size_t size; // user-defined copy assignment (non copy-and-swap idiom) // note: copy-and-swap would always reallocate resources C& operator=(const C& other) { if (this != &other) // not a self-assignment { if (size != other.size) // resource cannot be reused { data.reset(new int[other.size]); size = other.size; } std::copy(&other.data[0], &other.data[0] + size, &data[0]); } return *this; } }; int main() { A a1, a2; std::cout << "a1 = a2 calls "; a1 = a2; // user-defined copy assignment B b1, b2; b2.s1 = "foo"; b2.s2 = "bar"; std::cout << "b1 = b2 calls "; b1 = b2; // implicitly-defined copy assignment std::cout << "b1.s1 = " << b1.s1 << "; b1.s2 = " << b1.s2 << '\n'; }
Output:
a1 = a2 calls copy assignment of A b1 = b2 calls copy assignment of A b1.s1 = foo; b1.s2 = bar
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
CWG 1353 | C++98 | the conditions where implicitly-declared copy assignment operators are undefined did not consider multi-dimensional array types |
consider these types |
CWG 2094 | C++11 | a volatile subobject made defaulted copy assignment operators non-trivial (CWG issue 496) |
triviality not affected |
CWG 2171 | C++11 | operator=(X&) = default | made trivial |
CWG 2180 | C++11 | a defaulted copy assignment operator for class T was not defined as deletedif T is abstract and has non-copy-assignable direct virtual base classes
|
the operator is defined as deleted in this case |
CWG 2595 | C++20 | a copy assignment operator was not eligible if there is another copy assignment operator which is more constrained but does not satisfy its associated constraints |
it can be eligible in this case |