std::chrono::year::operator++, std::chrono::year::operator--
From cppreference.com
|
constexpr
std::chrono::year
& operator++
(
)
noexcept
;
|
(1) | (since C++20) |
|
constexpr
std::chrono::year operator++
(
int
)
noexcept
;
|
(2) | (since C++20) |
|
constexpr
std::chrono::year
& operator--
(
)
noexcept
;
|
(3) | (since C++20) |
|
constexpr
std::chrono::year operator--
(
int
)
noexcept
;
|
(4) | (since C++20) |
Adds or subtracts 1 from the year value.
1,2) Performs
*this +
=
std::chrono::years
{
1
}
;
3,4) Performs
*this -
=
std::chrono::years
{
1
}
;
Parameters
(none)
Return value
1,3) A reference to this
year after modification.2,4) A copy of the
year made before modification.Notes
If the result would be outside the range
[
-32767
,
32767
]
Example
Run this code
#include <chrono> #include <iostream> int main() { std::cout << std::boolalpha; std::chrono::year y{2020}; std::cout << (++y == std::chrono::year(2021)) << ' '; std::cout << (--y == std::chrono::year(2020)) << '\n'; using namespace std::literals::chrono_literals; y = 32767y; y++; //← unspecified, see ↑ Notes ↑ std::cout << static_cast<int>(y) << '\n'; }
Possible output:
true true -32768
See also
adds or subtracts a number of years from a year (public member function) |
|
|
(C++20)
|
performs arithmetic on years (function) |