std::chrono::operator+, std::chrono::operator- (std::chrono::year)
From cppreference.com
|
constexpr
std::chrono::year operator+
(
const
std::chrono::year
& y,
const std::chrono::years & ys ) noexcept ; |
(1) | (since C++20) |
|
constexpr
std::chrono::year operator+
(
const
std::chrono::years
& ys,
const std::chrono::year & y ) noexcept ; |
(2) | (since C++20) |
|
constexpr
std::chrono::year operator-
(
const
std::chrono::year
& y,
const std::chrono::years & ys ) noexcept ; |
(3) | (since C++20) |
|
constexpr
std::chrono::years operator-
(
const
std::chrono::year
& y1,
const std::chrono::year & y2 ) noexcept ; |
(4) | (since C++20) |
1,2) Adds ys.count() years to y
3) Subtracts ys.count() years from y
4) Returns the difference in years between y1 and y2.
Return value
1,2)
std::chrono::year
(
int
(y)
+ ys.count
(
)
)
3)
std::chrono::year
(
int
(y)
- ys.count
(
)
)
4)
std::chrono::years
(
int
(y1)
-
int
(y2)
)
Notes
If the resulting year value for (1-3) is outside the range
[
-32767
,
32767
]
The result of subtracting two year values is a duration of type std::chrono::years
2018y - 2017y is
std::chrono::years
(
1
)
Example
Run this code
#include <cassert> #include <chrono> int main() { std::chrono::year y{2020}; y = std::chrono::years(12) + y; // overload (2): duration + time point assert(y == std::chrono::year(2032)); y = y - std::chrono::years(33); // overload (3): time point - duration assert(y == std::chrono::year(1999)); // y = std::chrono::years(33) - y; // not supported: duration - time point using namespace std::chrono; constexpr std::chrono::years ys = 2025y - 2020y; // overload (4) static_assert(ys == std::chrono::years(5)); }
See also
| increments or decrements the month (public member function of std::chrono::month) |
|
| adds or subtracts a number of months (public member function of std::chrono::month) |