std::compare_weak_order_fallback
Defined in header <compare>
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||
inline
namespace
/* unspecified */
{
inline
constexpr
/* unspecified */
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(since C++20) | |
Call signature |
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template
<
class T, class U >
requires /* see below */ |
(since C++20) | |
Performs three-way comparison on subexpressions
t and u and produces a result of type std::weak_ordering, even if the operator <=>
If std::decay_t<T> and std::decay_t<U> are the same type, std::compare_weak_order_fallback(t, u) is expression-equivalent
- std::weak_order(t, u)
-
t == u ? std::
weak_ordering
::
equivalent
:
t < u ? std:: weak_ordering :: less :
std::weak_ordering::greater , if the expressions t == u and t < u are both well-formed and each of decltype(t == u) and decltype(t < u) models boolean-testable, except that t and u
In all other cases, std::compare_weak_order_fallback(t, u) is ill-formed, which can result in substitution failure
Customization point objects
The name std::compare_weak_order_fallback
denotes a customization point object, which is a const function object of a literal
semiregular
class type. For exposition purposes, the cv-unqualified version of its type is denoted as __compare_weak_order_fallback_fn
All instances of __compare_weak_order_fallback_fn
are equal. The effects of invoking different instances of type
__compare_weak_order_fallback_fn
on the same arguments are equivalent, regardless of whether the expression denoting the instance is an lvalue or rvalue, and is const-qualified or not (however, a volatile-qualified instance is not required to be invocable). Thus, std::compare_weak_order_fallback
Given a set of types Args...
, if
std::declval
<Args>
(
)
meet the requirements for arguments to std::compare_weak_order_fallback
above, __compare_weak_order_fallback_fn
models
- std::invocable <__compare_weak_order_fallback_fn, Args...>
- std::invocable < const __compare_weak_order_fallback_fn, Args...>
- std::invocable <__compare_weak_order_fallback_fn&, Args...>
-
std::invocable
<
const __compare_weak_order_fallback_fn&, Args...>
.
Otherwise, no function call operator of __compare_weak_order_fallback_fn
participates in overload resolution.
Example
#include <compare> #include <iostream> // does not support <=> struct Rational_1 { int num; int den; // > 0 }; inline constexpr bool operator<(Rational_1 lhs, Rational_1 rhs) { return lhs.num * rhs.den < rhs.num * lhs.den; } inline constexpr bool operator==(Rational_1 lhs, Rational_1 rhs) { return lhs.num * rhs.den == rhs.num * lhs.den; } // supports <=> struct Rational_2 { int num; int den; // > 0 }; inline constexpr std::weak_ordering operator<=>(Rational_2 lhs, Rational_2 rhs) { return lhs.num * rhs.den <=> rhs.num * lhs.den; } inline constexpr bool operator==(Rational_2 lhs, Rational_2 rhs) { return lhs <=> rhs == 0; } void print(int id, std::weak_ordering value) { std::cout << id << ") "; if (value == 0) std::cout << "equal\n"; else if (value < 0) std::cout << "less\n"; else std::cout << "greater\n"; } int main() { Rational_1 a{1, 2}, b{3, 4}; // print(0, a <=> b); // does not work print(1, std::compare_weak_order_fallback(a, b)); // works, defaults to < and == Rational_2 c{6, 5}, d{8, 7}; print(2, c <=> d); // works print(3, std::compare_weak_order_fallback(c, d)); // works Rational_2 e{2, 3}, f{4, 6}; print(4, e <=> f); // works print(5, std::compare_weak_order_fallback(e, f)); // works }
Output:
1) less 2) greater 3) greater 4) equal 5) equal
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 2114 (P2167R3) |
C++20 | the fallback mechanism only required return types to be convertible to bool |
constraints strengthened |
See also
(C++20)
|
performs 3-way comparison and produces a result of type std::weak_ordering (customization point object) |