std::ranges::subrange<I,S,K>::advance
From cppreference.com
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constexpr subrange& advance(
std::iter_difference_t
<I> n )
;
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(since C++20) | |
Increments or decrements begin_ :
- If
Imodelsbidirectional_iteratorand n < 0 is true, decrementsbegin_by -n
- Equivalent to:
ranges::advance(
begin_, n);
if constexpr (StoreSize)
size_+=to-unsigned-like(-n);
return *this;
- Equivalent to:
auto d = n -
ranges::advance
(
begin_, n,end_);
if constexpr (StoreSize)
size_-=to-unsigned-like(d);
return *this;
According to the preconditions of ranges::advance, if n < 0 is true and begin_ cannot be decremented by -n
Parameters
| n | - | number of maximal increments of the iterator |
Return value
*this
Example
Run this code
#include <algorithm> #include <array> #include <iostream> #include <iterator> #include <ranges> void print(auto name, auto const sub) { std::cout << name << ".size() == " << sub.size() << "; { "; std::ranges::for_each(sub, [](int x) { std::cout << x << ' '; }); std::cout << "}\n"; }; int main() { std::array arr{1, 2, 3, 4, 5, 6, 7}; std::ranges::subrange sub{std::next(arr.begin()), std::prev(arr.end())}; print("1) sub", sub); print("2) sub", sub.advance(3)); print("3) sub", sub.advance(-2)); }
Output:
1) sub.size() == 5; { 2 3 4 5 6 }
2) sub.size() == 2; { 5 6 }
3) sub.size() == 4; { 3 4 5 6 }Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
|---|---|---|---|
| LWG 3433 | C++20 | the behavior was undefined if n < 0 | made well-defined if begin_ can be decremented
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See also
obtains a copy of the subrange with its iterator advanced by a given distance (public member function) |
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obtains a copy of the subrange with its iterator decremented by a given distance (public member function) |
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| advances an iterator by given distance (function template) |
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(C++20)
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advances an iterator by given distance or to a given bound (algorithm function object) |