std::experimental::propagate_const<T>::operator=
From cppreference.com
< cpp | experimental | propagate const
|
constexpr propagate_const& operator=
( propagate_const&& p )
=
default
;
|
(1) | (library fundamentals TS v2) |
|
template
<
class U >
constexpr propagate_const& operator= ( propagate_const<U> && pu ) ; |
(2) | (library fundamentals TS v2) |
|
template
<
class U >
constexpr propagate_const& operator= ( U&& u ) ; |
(3) | (library fundamentals TS v2) |
|
propagate_const& operator=
(
const propagate_const&
)
= delete;
|
(4) | (library fundamentals TS v2) |
Let t_ designate the private data member that is the wrapped pointer-like object.
1) Explicitly defaulted move assignment operator that move assigns this->t_ from p.t_
2) Assigns std::move(pu.t_) to this->t_.
This overload participates in overload resolution only if
This overload participates in overload resolution only if
U is implicitly convertible to T
3) Assigns
std::forward
<U>
(u)
to this->t_.
This overload participates in overload resolution only if
This overload participates in overload resolution only if
U is implicitly convertible to T and
std::decay_t<U>
is not a specialization of propagate_const
4) Copy assignment operator is explicitly deleted.
propagate_const is non-copyable.Parameters
| p | - | another propagate_const object to move from
|
| pu | - | another propagate_const object of a different specialization to move from
|
| u | - | another object to assign to the contained pointer |
Return value
*this.