std::unordered_set<Key,Hash,KeyEqual,Allocator>::begin, std::unordered_set<Key,Hash,KeyEqual,Allocator>::
From cppreference.com
< cpp | container | unordered set
iterator begin() noexcept; |
(1) | (since C++11) |
const_iterator begin() const noexcept; |
(2) | (since C++11) |
const_iterator cbegin() const noexcept; |
(3) | (since C++11) |
Returns an iterator to the first element of the unordered_set
.
If the unordered_set
is empty, the returned iterator will be equal to end().
Parameters
(none)
Return value
Iterator to the first element.
Complexity
Constant.
Notes
Because both iterator
and const_iterator
Example
Run this code
#include <iostream> #include <unordered_set> struct Point { double x, y; }; int main() { Point pts[3] = {{1, 0}, {2, 0}, {3, 0}}; // points is a set containing the addresses of points std::unordered_set<Point*> points = { pts, pts + 1, pts + 2 }; // Change each y-coordinate of (i, 0) from 0 into i^2 and print the point for (auto iter = points.begin(); iter != points.end(); ++iter) { (*iter)->y = ((*iter)->x) * ((*iter)->x); // iter is a pointer-to-Point* std::cout << "(" << (*iter)->x << ", " << (*iter)->y << ") "; } std::cout << '\n'; // Now using the range-based for loop, we increase each y-coordinate by 10 for (Point* i : points) { i->y += 10; std::cout << "(" << i->x << ", " << i->y << ") "; } }
Possible output:
(3, 9) (1, 1) (2, 4) (3, 19) (1, 11) (2, 14)
See also
returns an iterator to the end (public member function) |
|
(C++11)(C++14)
|
returns an iterator to the beginning of a container or array (function template) |