std::chrono::year_month_weekday::operator+=, std::chrono::year_month_weekday::operator-=
From cppreference.com
< cpp | chrono | year month weekday
constexpr
std::chrono::year_month_weekday
&
operator+ = ( const std::chrono::years & dy ) const noexcept ; |
(1) | (since C++20) |
constexpr
std::chrono::year_month_weekday
&
operator+ = ( const std::chrono::months & dm ) const noexcept ; |
(2) | (since C++20) |
constexpr
std::chrono::year_month_weekday
&
operator- = ( const std::chrono::years & dy ) const noexcept ; |
(3) | (since C++20) |
constexpr
std::chrono::year_month_weekday
&
operator- = ( const std::chrono::months & dm ) const noexcept ; |
(4) | (since C++20) |
Modifies the time point *this represents by the duration dy or dm
1) Equivalent to *this = *this + dy;
2) Equivalent to *this = *this + dm;
3) Equivalent to *this = *this - dy;
4) Equivalent to *this = *this - dm;
For durations that are convertible to both std::chrono::years and std::chrono::months, the years
overloads (1,3)
Example
Run this code
#include <cassert> #include <chrono> #include <iostream> int main() { auto ymwi{1/std::chrono::Wednesday[2]/2021}; std::cout << ymwi << '\n'; ymwi += std::chrono::years(5); std::cout << ymwi << '\n'; assert(static_cast<std::chrono::year_month_day>(ymwi) == std::chrono::year(2026)/1/14); ymwi -= std::chrono::months(1); std::cout << ymwi << '\n'; assert(static_cast<std::chrono::year_month_day>(ymwi) == std::chrono::day(10)/12/2025); }
Output:
2021/Jan/Wed[2] 2026/Jan/Wed[2] 2025/Dec/Wed[2]
See also
(C++20)
|
adds or subtracts a year_month_weekday and some number of years or months (function) |