std::chrono::operator+, std::chrono::operator- (std::chrono::year_month_day_last)

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C-style date and time
std::chrono::year_month_day_last
Defined in header <chrono>
constexpr std::chrono::year_month_day_last

operator+ ( const std::chrono::year_month_day_last & ymdl,

const std::chrono::months & dm ) noexcept ;
(since C++20)
constexpr std::chrono::year_month_day_last

operator+ ( const std::chrono::months & dm,

const std::chrono::year_month_day_last & ymdl ) noexcept ;
(since C++20)
constexpr std::chrono::year_month_day_last

operator+ ( const std::chrono::year_month_day_last & ymdl,

const std::chrono::years & dy ) noexcept ;
(since C++20)
constexpr std::chrono::year_month_day_last

operator+ ( const std::chrono::years & dy,

const std::chrono::year_month_day_last & ymdl ) noexcept ;
(since C++20)
constexpr std::chrono::year_month_day_last

operator- ( const std::chrono::year_month_day_last & ymdl,

const std::chrono::months & dm ) noexcept ;
(since C++20)
constexpr std::chrono::year_month_day_last

operator- ( const std::chrono::year_month_day_last & ymdl,

const std::chrono::years & dy ) noexcept ;
(since C++20)
1,2) Adds dm.count() months to the date represented by ymdl. The result has the same year() and month() as std::chrono::year_month (ymdl.year ( ), ymdl.month ( ) ) +
3,4) Adds dy.count() years to the date represented by ymdl. The result is equivalent to std::chrono::year_month_day_last (ymdl.year ( ) + dy, ymdl.month_day_last ( ) )
5) Subtracts dm.count() months from the date represented by ymdl. Equivalent to ymdl + -dm
6) Subtracts dy.count() years from the date represented by ymdl. Equivalent to ymdl + -dy

For durations that are convertible to both std::chrono::years and std::chrono::months, the years overloads (3,4,6)

Example

Run this code
#include <cassert>
#include <chrono>
#include <iostream>
 
int main()
{
    auto ymdl{11/std::chrono::last/2020};
    std::cout << ymdl << '\n';
 
    ymdl = std::chrono::years(10) + ymdl;
    std::cout << ymdl << '\n';
    assert(ymdl == std::chrono::day(30)/
                   std::chrono::November/
                   std::chrono::year(2030));
 
    ymdl = ymdl - std::chrono::months(6);
    std::cout << ymdl << '\n';
    assert(ymdl == std::chrono::day(31)/
                   std::chrono::May/
                   std::chrono::year(2030));
}

Output: 

2020/Nov/last
2030/Nov/last
2030/May/last
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