std::chrono::year_month::operator+=, std::chrono::year_month::operator-=
From cppreference.com
< cpp | chrono | year month
constexpr
std::chrono::year_month
&
operator+ = ( const std::chrono::years & dy ) const noexcept ; |
(1) | (since C++20) |
constexpr
std::chrono::year_month
&
operator+ = ( const std::chrono::months & dm ) const noexcept ; |
(2) | (since C++20) |
constexpr
std::chrono::year_month
&
operator- = ( const std::chrono::years & dy ) const noexcept ; |
(3) | (since C++20) |
constexpr
std::chrono::year_month
&
operator- = ( const std::chrono::months & dm ) const noexcept ; |
(4) | (since C++20) |
Modifies the time point *this represents by the duration dy or dm
1) Equivalent to *this = *this + dy;
2) Equivalent to *this = *this + dm;
3) Equivalent to *this = *this - dy;
4) Equivalent to *this = *this - dm;
For durations that are convertible to both std::chrono::years and std::chrono::months, the years
overloads (1,3)
Example
Run this code
#include <cassert> #include <chrono> int main() { auto ym{std::chrono::day(1)/7/2023}; ym -= std::chrono::years{2}; assert(ym.month() == std::chrono::July); assert(ym.year() == std::chrono::year(2021)); ym += std::chrono::months{7}; assert(ym.month() == std::chrono::month(2)); assert(ym.year() == std::chrono::year(2022)); }
See also
(C++20)
|
performs arithmetic on year_month (function) |