std::chrono::duration<Rep,Period>::operator+=, -=, *=, /=, %=
From cppreference.com
(1) | ||
duration& operator+
=
(
const duration& d )
;
|
(since C++11) (constexpr since C++17) |
|
(2) | ||
duration& operator-
=
(
const duration& d )
;
|
(since C++11) (constexpr since C++17) |
|
(3) | ||
duration& operator*
=
(
const rep& rhs )
;
|
(since C++11) (constexpr since C++17) |
|
(4) | ||
duration& operator/
=
(
const rep& rhs )
;
|
(since C++11) (constexpr since C++17) |
|
(5) | ||
duration& operator%
=
(
const rep& rhs )
;
|
(since C++11) (constexpr since C++17) |
|
(6) | ||
duration& operator%
=
(
const duration& rhs )
;
|
(since C++11) (constexpr since C++17) |
|
Performs compound assignments between two durations with the same period or between a duration and a tick count value.
If rep_
is the member variable holding the number of ticks in this duration object,
1) Equivalent to
rep_ +
= d.count
(
)
;
return
*this;
2) Equivalent to
rep_ -
= d.count
(
)
;
return
*this;
3) Equivalent to rep_ *= rhs; return *this;
4) Equivalent to rep_ /= rhs; return *this;
5) Equivalent to rep_ %= rhs; return *this;
6) Equivalent to
rep_ %
= d.count
(
)
;
return
*this;
Parameters
d | - | duration on the right-hand side of the operator |
rhs | - | number of ticks on the right-hand side of the operator |
Return value
A reference to this duration after modification.
Example
Run this code
#include <chrono> #include <iostream> int main() { std::chrono::minutes m(11); m *= 2; m += std::chrono::hours(10); // hours implicitly convert to minutes std::cout << m.count() << " minutes equals " << std::chrono::duration_cast<std::chrono::hours>(m).count() << " hours and "; m %= std::chrono::hours(1); std::cout << m.count() << " minutes\n"; }
Output:
622 minutes equals 10 hours and 22 minutes
See also
increments or decrements the tick count (public member function) |
|
implements arithmetic operations with durations as arguments (function template) |